Four point charges -Q,-q,2q and 2Q are placed, one at each corner of the square. The relation between Q and q fo which the potential at the centre of the square is zero, is
Q=q
Q=1q
Q=−q
Q=−1q
A
Q=−q
B
Q=q
C
Q=1q
D
Q=−1q
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Solution
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Let the side of the square be =a
Potential at centre
Vc=K×−Qa√2+K×−qa√2+K×2qa√2+K×2Qa√2
0=KQa√2+Kqa√2
⇒Q=−q
Option (C) is correct
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