Four times a certain two digit number is seven times the number obtained on interchanging its digits.If the difference between the digits is $4$ ; find the number.

Question

Four times a certain two digit number is seven times the number obtained on interchanging its digits-If the difference between the digits is 4- the number- 39668492

Toppr Admin · Accepted Answer

Let the ones digit be -x2032-x-x2032-The ten-apos-s digit is x-4-Original number -10-x-4-x-11x-40Reversed number -10x-x-4-11x-44-11x-40-7-11x-4-44x-160-77x-2833x-132-x2234-x-4Ten-apos-s digit -x-4-8Therefore- the number is -84-

Four times a certain two digit number is seven times the number obtained on interchanging its digits.If the difference between the digits is $4$ ; find the number.
$39$
$66$
$84$
$92$

Let the ones digit be $^{'} x^{'}$
The ten's digit is $x + 4$ .
Original number $= 10 (x + 4) + x = 11 x + 40$
Reversed number $= 10 x + x + 4 = 11 x + 4$
$4 (11 x + 40) = 7 (11 x + 4) 44 x + 160 = 77 x + 28 33 x = 132 ∴ x = 4$
Ten's digit $= x + 4 = 8$
Therefore, the number is $= 84$ .

Four times a certain two digit number is seven times the number obtained on interchanging its digits.If the difference between the digits is 4; find the number. 39668492

Let the ones digit be ′x′The ten's digit is x+4.Original number =10(x+4)+x=11x+40Reversed number =10x+x+4=11x+44(11x+40)=7(11x+4)44x+160=77x+2833x=132∴x=4Ten's digit =x+4=8Therefore, the number is =84.

Four times a certain two digit number is seven times the number obtained on interchanging its digits.If the difference between the digits is $4$ ; find the number.
$39$
$66$
$84$
$92$

Let the ones digit be $^{'} x^{'}$
The ten's digit is $x + 4$ .
Original number $= 10 (x + 4) + x = 11 x + 40$
Reversed number $= 10 x + x + 4 = 11 x + 4$
$4 (11 x + 40) = 7 (11 x + 4) 44 x + 160 = 77 x + 28 33 x = 132 ∴ x = 4$
Ten's digit $= x + 4 = 8$
Therefore, the number is $= 84$ .