Assertion :Vectors →a,→b,→c are coplanar. Reason: (x→a+y→b)=→0⇒ x = 0 and y = 0.
View Solution
Q2
Find the angles between each of the following pairs of straight lines:
(i) 3x + y + 12 = 0 and x + 2y − 1 = 0
(ii) 3x − y + 5 = 0 and x − 3y + 1 = 0
(iii) 3x + 4y − 7 = 0 and 4x − 3y + 5 = 0
(iv) x − 4y = 3 and 6x − y = 11
(v) (m2 − mn) y = (mn + n2) x + n3 and (mn + m2) y = (mn − n2) x + m3.
View Solution
Q3
The shortest distance between the point (32,0) and the curve y=√x,(x>0), is :
View Solution
Q4
The Equation y = - 5, in two variables can be written in the form of ax + by + c = 0 as
View Solution
Q5
The differential equation obtained by eliminating the arbitrary constants a and b in y=acos(nx+b) is