Solve Study Textbooks

Join / Login

Question

$(\frac{1 1}{- 1 5}) (\frac{- 7}{1 0}) + (\frac{- 3}{2 0}) (\frac{7}{3 0})$

Easy

Open in App

Solution

Verified by Toppr

$(\frac{- 1 1 \times - 7}{1 5 \times 1 0}) + (\frac{- 3 \times 7}{2 0 \times 3 0}) \frac{7 7}{1 5 0} - \frac{2 1}{6 0 0} \frac{3 0 8 - 2 1}{6 0 0} \frac{2 8 7}{6 0 0}$

Was this answer helpful?

0

0

Similar questions

Arrange the following rational numbers in descending order:
(i) $- 2, \frac{- 1 3}{6}, \frac{8}{- 3}, \frac{1}{3}$
(ii) $\frac{- 3}{1 0}, \frac{7}{- 1 0}, \frac{- 1 1}{2 0}, \frac{1 7}{- 3 0}$
(iii) $\frac{- 5}{6}, \frac{- 7}{1 2}, \frac{- 1 3}{1 8}, \frac{2 3}{- 2 4}$
(iv) $\frac{- 1 0}{1 1}, \frac{- 1 9}{2 2}, \frac{- 2 3}{3 3}, \frac{- 3 9}{4 4}$

$\frac{1 5}{4} + \frac{5}{4}$

If $x = 1 + \frac{1}{3 + \frac{1}{2 + \frac{1}{3 + \frac{1}{2 . 0 0}}}} .$ Then value of $x$ is

Solve $\frac{n + 3}{\frac{1}{3}} - \frac{n + 2}{\frac{1}{2}} = \frac{n - 4}{\frac{1}{1 0}}$ . Then the value of $n$ is obtained as

$\frac{p + 7}{p - 6} = \frac{1}{3}$

View more