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Question

Using distributivity, find
${\frac{9}{16} \times \frac{4}{12}} + {\frac{9}{16} \times \frac{- 3}{9}} =$

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Solution

Verified by Toppr

$(\frac{9}{16} \times \frac{4}{12}) + (\frac{9}{16} \times \frac{- 3}{9})$
$= (\frac{36}{192}) + (\frac{- 27}{144})$
$= (\frac{3}{16}) + (\frac{- 3}{16})$
$= \frac{3 - 3}{16}$
$= 0$
Hence,
${\frac{9}{16} \times \frac{4}{12}} + {\frac{9}{16} \times \frac{- 3}{9}} = 0$

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