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Thus mass of original disc=$M=σπR_{2}$

Radius of smaller disc=$R/2$.

Thus mass of the smaller disc=$σπ(R/2)_{2}=M/4$

After the smaller disc has been cut from the original, the remaining portion is considered to be a system of two masses. The two masses are:

M(concentrated at O), and -M(=M/4) concentrated at O'

(The negative sign indicates that this portion has been removed from the original disc.)

Let*x* be the distance through which the centre of mass of the remaining portion shifts from point O.

Let

The relation between the centres of masses of two masses is given as:

$x=(m_{1}r_{1}+m_{2}r_{2})/(m_{1}+m_{2})$

$=(M×0−(M/4)×(R/2))/(M−M/4)=−R/6$

(The negative sign indicates that the centre of mass gets shifted toward the left of point O)

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