From the adjoining figure- calculate the value of a- b and c-a- - 38-circ- b- - 52-circ- and c- - 38-circ-a- - 48-circ- b- - 42-circ- and c- - 38-circ-a- - 36-circ- b- - 52-circ- and c- - 40-circ-a- - 39-circ- b- - 51-circ- and c- - 38-circ-

Question

Toppr Admin · Accepted Answer

Sum of all angles of a triangle -180o-x2234-a-110o-32o-180o-x2234-a-38-x2218-

From the adjoining figure, calculate the value of a, b and c.

$a = 38^{\circ}, b = 52^{\circ}$ and $c = 38^{\circ}$
$a = 48^{\circ}, b = 42^{\circ}$ and $c = 38^{\circ}$
$a = 36^{\circ}, b = 52^{\circ}$ and $c = 40^{\circ}$
$a = 39^{\circ}, b = 51^{\circ}$ and $c = 38^{\circ}$

Sum of all angles of a triangle $= 180^{o}$
$∴ a + 110^{o} + 32^{o} = 180^{o}$
$∴ a = 38^{\circ}$

From the adjoining figure, calculate the value of a, b and c.a=38∘,b=52∘ and c=38∘a=48∘,b=42∘ and c=38∘a=36∘,b=52∘ and c=40∘a=39∘,b=51∘ and c=38∘

Sum of all angles of a triangle =180o∴a+110o+32o=180o∴a=38∘

From the adjoining figure, calculate the value of a, b and c.

$a = 38^{\circ}, b = 52^{\circ}$ and $c = 38^{\circ}$
$a = 48^{\circ}, b = 42^{\circ}$ and $c = 38^{\circ}$
$a = 36^{\circ}, b = 52^{\circ}$ and $c = 40^{\circ}$
$a = 39^{\circ}, b = 51^{\circ}$ and $c = 38^{\circ}$

Sum of all angles of a triangle $= 180^{o}$
$∴ a + 110^{o} + 32^{o} = 180^{o}$
$∴ a = 38^{\circ}$