From the following data of heats of combustion, find the heat of formation of ${C H}_{3} O H (l)$ :
${C H}_{3} O H (l) + \frac{3}{2} O_{2} (g) ⟶ C O_{2} (g) + 2 H_{2} O (l); Δ H = - 726 k J$
$C (s) + O_{2} (g) ⟶ C O_{2} (g); Δ H = - 394 k J$
$H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 286 k J$

Question

From the following data of heats of combustion, find the heat of formation of

{C H}_{3} O H (l)

:

{C H}_{3} O H (l) + \frac{3}{2} O_{2} (g) ⟶ C O_{2} (g) + 2 H_{2} O (l); Δ H = - 726 k J

C (s) + O_{2} (g) ⟶ C O_{2} (g); Δ H = - 394 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 286 k J

Toppr Admin · Accepted Answer

CH3OH-l-32O2-g-x2192-CO2-g-2H2O-l-x25B3-rH-x2296-x2212-726kJ-i-C-s-O2-g-x2192-CO2-g-x394-H-x2212-394kJ-ii-xA0-H2-g-12O2-g-x2192-H2O-l-x394-H-x2212-286kJ-iii-On adding the equation as -ii-2-xD7-iii- we get-xA0-C-s-2H2-g-2O2-g-x2192-CO2-g-2H2O-l-x21D2-x2212-394-2-xD7-x2212-286-x2212-966kJ-iv-xA0-Reversing the -i- reaction- we get-xA0-CO2-g-2H2O-l-x2192-CH3OH-l-32O2-g-x21D2-726kJ -v-iv- - -v-C-s-2H2-g-12O2-g-x2192-CH3OH-l-x21D2-x2212-966-726-240kJ-xA0-

From the following data of heats of combustion, find the heat of formation of CH3OH(l)CH3OH(l)+32O2(g)→CO2(g)+2H2O(l);△rH⊖=−726kJC(s)+O2(g)→CO2(g),ΔH=−394kJ H2(g)+12O2(g)→H2O(l),ΔH=−286kJ