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Question

From the graph shown, the value of Work function if the stopping potential, V, and frequency of the incident light 'v' are on y and x- axes respectively is
20664_7b27f6df95bd4b18977f342ed66493c1.png
  1. 1eV
  2. 2eV
  3. 4eV
  4. 3eV

A
1eV
B
2eV
C
3eV
D
4eV
Solution
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hv=hv0+K.E
at stopping potential K.E=eV
hv=hv0+eV
V=he(vv0)
from the graph for v=0
work function ϕ=hv0=3eV.

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