General electronic configuration of outermost and penultimate shell is $[N e] (n - 1) s^{2} (n - 1) p^{6} (n - 1) d^{5} n s^{2}$ . If $n = 4$ , then the number of protons in the nucleus will be:

Question

General electronic configuration of outermost and penultimate shell is -Ne-n-1-s-2-n-1-p-6-n-1-d-5-ns-2- If n - 4- then the number of protons in the nucleus will be- 24- 252530

Toppr Admin · Accepted Answer

Substituting the values- we get the configuration to be-xA0-Ne-3s23p64s23d5-xA0-The atomic number is 10-2-6-2-5-25-Number of proton - Atomic numberTherefore- the number of protons in the nucleus is 25-Hence- option C is correct-

General electronic configuration of outermost and penultimate shell is $[N e] (n - 1) s^{2} (n - 1) p^{6} (n - 1) d^{5} n s^{2}$ . If $n = 4$ , then the number of protons in the nucleus will be:
$> 24$
$> 25$
$25$
$30$

Substituting the values, we get the configuration to be $[N e] 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{5}$ .

The atomic number is $10 + 2 + 6 + 2 + 5 = 25$ .

Number of proton = Atomic number

Therefore, the number of protons in the nucleus is $25.$

Hence, option C is correct.

General electronic configuration of outermost and penultimate shell is [Ne](n−1)s2(n−1)p6(n−1)d5ns2. If n=4, then the number of protons in the nucleus will be:>24>252530

Substituting the values, we get the configuration to be [Ne]3s23p64s23d5. The atomic number is 10+2+6+2+5=25.Number of proton = Atomic numberTherefore, the number of protons in the nucleus is 25.Hence, option C is correct.

General electronic configuration of outermost and penultimate shell is $[N e] (n - 1) s^{2} (n - 1) p^{6} (n - 1) d^{5} n s^{2}$ . If $n = 4$ , then the number of protons in the nucleus will be:
$> 24$
$> 25$
$25$
$30$

Substituting the values, we get the configuration to be $[N e] 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{5}$ .

The atomic number is $10 + 2 + 6 + 2 + 5 = 25$ .

Number of proton = Atomic number

Therefore, the number of protons in the nucleus is $25.$

Hence, option C is correct.