Give reasons-i- -BF-3- has zero dipole moment although the B-F bonds are polar-ii- NaCl is harder than Na metal-

Question

Toppr Admin · Accepted Answer

-i- Resultant dipoles cancel out each other-xA0-x2234-Dipolemoment-0-ii- NaCl is harder than Na because NaCl contain-xA0-Na-Size-Na-lt-Na- smaller the size more is hardness-

Give reasons:
(i) ${B F}_{3}$ has zero dipole moment although the $B - F$ bonds are polar.
(ii) $N a C l$ is harder than $N a$ metal.

$(i)$ Resultant dipoles cancel out each other $∴ D i p o l e m o m e n t = 0$
$(i i)$ $N a C l$ is harder than $N a$ because $N a C l$ contain ${N a}^{+}, S i z e : {N a}^{+} < N a$ , smaller the size more is hardness.

Give reasons:(i) BF3 has zero dipole moment although the B−F bonds are polar.(ii) NaCl is harder than Na metal.

(i) Resultant dipoles cancel out each other ∴Dipolemoment=0(ii) NaCl is harder than Na because NaCl contain Na+,Size:Na+<Na, smaller the size more is hardness.

Give reasons:
(i) ${B F}_{3}$ has zero dipole moment although the $B - F$ bonds are polar.
(ii) $N a C l$ is harder than $N a$ metal.

$(i)$ Resultant dipoles cancel out each other $∴ D i p o l e m o m e n t = 0$
$(i i)$ $N a C l$ is harder than $N a$ because $N a C l$ contain ${N a}^{+}, S i z e : {N a}^{+} < N a$ , smaller the size more is hardness.