Give the decreasing order of reactivity of the following alkyl halides in the Williamson’s reaction.
$i . {(C H_{3})}_{3} C - C H_{2} B r$
$i i . C l C H_{2} C H = C H_{2}$
$i i i . C l C H_{2} C H_{2} C H_{3}$
$i v . B r C H_{2} C H_{2} C H_{3}$

Question

Give the decreasing order of reactivity of the following compounds with HBr-displaystyle III- II- IV- I-displaystyle III- IV- II- I-displaystyle II- III- IV- I-displaystyle III- II- I- IV-

Toppr Admin · Accepted Answer

The decreasing order of reactivity with HBr is as shown- When electron donating groups such as methoxy group or methyl group are present in para position- the reactivity is high- When electron releasing groups are absent or if they are present in meta position- the reactivity is low-

Give the decreasing order of reactivity of the following compounds with HBr.

$I I I > I I > I V > I .$
$I I I > I V > I I > I .$
$I I > I I I > I V > I .$
$I I I > I I > I > I V .$

The decreasing order of reactivity with HBr is as shown. When electron donating groups such as methoxy group or methyl group are present in para position, the reactivity is high. When electron releasing groups are absent or if they are present in meta position, the reactivity is low.

Give the decreasing order of reactivity of the following compounds with HBr.III>II>IV>I.III>IV>II>I.II>III>IV>I.III>II>I>IV.

The decreasing order of reactivity with HBr is as shown. When electron donating groups such as methoxy group or methyl group are present in para position, the reactivity is high. When electron releasing groups are absent or if they are present in meta position, the reactivity is low.

Give the decreasing order of reactivity of the following compounds with HBr.

$I I I > I I > I V > I .$
$I I I > I V > I I > I .$
$I I > I I I > I V > I .$
$I I I > I I > I > I V .$