0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Given a sequence of four numbers, first three of which are in GP and the last three are in AP with common difference 6. If first and last terms of this sequence are equal, then sum of the numbers
  1. 16
  2. 8
  3. 14
  4. 2

A
8
B
14
C
2
D
16
Solution
Verified by Toppr


1341456_1144815_ans_0ce1fe6522484378b3ed26b8146afee3.jpg

Was this answer helpful?
2
Similar Questions
Q1
Given a sequence of 4 numbers, first three of which are in G.P. and last three are in A.P. with common difference three. If first and last terms of this sequence are equal, then last term is

View Solution
Q2

Out of four number in a sequence,first three are in GP with first term 2 and last three are in AP with common difference 12. Find the common ratio, if the number are positive.


View Solution
Q3

Out of the four number given, first three are in GP and last three are in AP whose common difference is 6. If the first and last numbers are same,then first term will be


View Solution
Q4
Given a sequence of 4 members, first three of which are in G.P. and the last three are in A.P. with common difference six. If first and last terms of this sequence are equal, then the last term is:
View Solution
Q5
In a set of four numbers the first three are in GP and the last three are in AP with common difference 6. If the first number is the same as the fourth then third number of this set is
View Solution