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Standard IX
Mathematics
Question
Given:
Δ
A
⊥
A
B
,
C
B
⊥
A
B
and
A
C
=
B
D
State
3
points of equal pairs in
Δ
A
B
C
&
Δ
A
B
D
& Congruence rule.
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Solution
Verified by Toppr
In
△
A
B
C
and
△
A
B
D
∠
A
=
∠
B
=
90
∘
[A]
A
C
=
B
D
⇒
A
D
=
B
C
[S]
A
D
∥
B
C
[S]
From SAS theorem
△
A
B
C
≅
△
A
B
D
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Similar Questions
Q1
Given:
Δ
A
⊥
A
B
,
C
B
⊥
A
B
and
A
C
=
B
D
State
3
points of equal pairs in
Δ
A
B
C
&
Δ
A
B
D
& Congruence rule.
View Solution
Q2
In
Δ
A
B
D
, AB = AD and AC is perpendicular to BD. State the congruence rule by which
Δ
A
C
B
≅
Δ
A
C
D
.
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Q3
In
Δ
A
B
D
, AB = AD and AC is perpendicular to BD. State the congruence rule by which
Δ
A
C
B
≅
Δ
A
C
D
.
View Solution
Q4
In the given figure, if AB = DC,
∠
A
B
D
=
∠
C
D
B
, which congruence rule would you apply to prove
Δ
A
B
D
=
Δ
C
D
B
?
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Q5
In the given figure,
∆ABC and ∆ABD are such that AD = BC, ∠1 = ∠2 and ∠3 = ∠4. Prove that BD = AC.
Figure
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