Given that HCF -306 and 657- - 9- LCM of -306 and 657-

Question

Toppr Admin · Accepted Answer

We know that-xA0-LCM x HCF - Product of the two numbersLCM-Product of two numbersHCFProduct of the two numbers -306-xD7-657-201042LCM -2010429LCM -22-338

Given that HCF $(306$ and $657) = 9$ , find LCM of $(306$ and $657)$

We know that,

$LCM x HCF = Product of the two numbers$

$L C M = \frac{Product of two numbers}{H C F}$

Product of the two numbers $= 306 \times 657 = 201042$

LCM $= \frac{201042}{9}$

LCM $= 22, 338$

Given that HCF (306 and 657)=9, find LCM of (306 and 657)

We know that, LCM x HCF = Product of the two numbersLCM=Product of two numbersHCFProduct of the two numbers =306×657=201042LCM =2010429LCM =22,338

Given that HCF $(306$ and $657) = 9$ , find LCM of $(306$ and $657)$

We know that,

$LCM x HCF = Product of the two numbers$

$L C M = \frac{Product of two numbers}{H C F}$

Product of the two numbers $= 306 \times 657 = 201042$

LCM $= \frac{201042}{9}$

LCM $= 22, 338$