Given- mathrm-E-mathrm-F-mathrm-e-3-mathrm-F-mathrm-e-o- -0-036mathrm-V- mathrm-E-mathrm-F-mathrm-e-2-mathrm-F-mathrm-e-o- -0-439 mathrm-V- The value of standard electrode potential the change- mathrm-F-mathrm-e-3-mathrm-a-mathrm-q-mathrm-e-rightarrow mathrm-F-mathrm-e-2-mathrm-a-mathrm-q- will be-0-385 mathrm-V-0-403mathrm-V-0-770mathrm-V-0-270mathrm-V-

Question

Toppr Admin · Accepted Answer

Fe3-3e-x2192-Fe-xA0-E1o-x2212-0-036VFe2-2e-x2192-Fe-xA0-E2o-x2212-0-439VFe3-aq-e-x2212-x2192-Fe2-aq-xA0-Eno-

Given, $E_{F e^{3 +} / F e}^{o} = - 0.036 V, E_{F e^{2 +} / F e}^{o} = - 0.439 V$ . The value of standard electrode potential for the change, $F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q)$ will be:
$0.385 V$
$- 0.403 V$
$0.770 V$
$- 0.270 V$

$F e^{3 +} + 3 e \to F e, {E_{1}}^{o} = - 0.036 V$

$F e^{2 +} + 2 e \to F e, {E_{2}}^{o} = - 0.439 V$

$F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q); {E_{n}}^{o} = ?$

Given, EoFe3+/Fe=−0.036V, EoFe2+/Fe=−0.439V. The value of standard electrode potential for the change, Fe3+(aq)+e−→Fe2+(aq) will be:0.385V−0.403V0.770V−0.270V

Fe3++3e→Fe, E1o=−0.036VFe2++2e→Fe, E2o=−0.439VFe3+(aq)+e−→Fe2+(aq); Eno=?

Given, $E_{F e^{3 +} / F e}^{o} = - 0.036 V, E_{F e^{2 +} / F e}^{o} = - 0.439 V$ . The value of standard electrode potential for the change, $F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q)$ will be:
$0.385 V$
$- 0.403 V$
$0.770 V$
$- 0.270 V$

$F e^{3 +} + 3 e \to F e, {E_{1}}^{o} = - 0.036 V$

$F e^{2 +} + 2 e \to F e, {E_{2}}^{o} = - 0.439 V$

$F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q); {E_{n}}^{o} = ?$