Ground state energy of H-atom is left-E-1-right- the velocity of photoelectrons emitted when photon of energy -E-2- strikes stationary -Li-2- ion in ground state will be-v-sqrt-dfrac-2left-E-2- - 9-E-1-right-m-v-sqrt-dfrac-2left-E-2- - -E-1-right-m-v-sqrt-dfrac-2left-E-2- - 3-E-1-right-m-v-sqrt-dfrac-2left-E-2- - 9-E-1-right-m-

Question

Toppr Admin · Accepted Answer

We know cSo for lithium atom E-E1-xD7-32 or 9E1Energy conversation pinciple-12mv2-E2-x2212-9E1v2-2-E2-x2212-9E1-mv-x221A-2-E2-x2212-9E1-m

Ground state energy of H-atom is (−E1), the velocity of photoelectrons emitted when photon of energy E2 strikes stationary Li2+ ion in ground state will be:v=√2(E2+9E1)mv=√2(E2−E1)mv=√2(E2−3E1)mv=√2(E2−9E1)m

We know cSo for lithium atom E=E1×32 or 9E1Energy conversation pinciple:12mv2=E2−9E1v2=2(E2−9E1)mv=√2(E2−9E1)m

We know c
So for lithium atom $E = E_{1} \times 3^{2}$ or $9 E_{1}$
Energy conversation pinciple:
$\frac{1}{2} m v^{2} = E_{2} - 9 E_{1}$

$v^{2} = \frac{2 (E_{2} - 9 E_{1})}{m}$

$v = \sqrt{\frac{2 (E_{2} - 9 E_{1})}{m}}$