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Question

Group displacement law states that the emission of $$\alpha$$ or $$\beta$$ particles results in the daughter element occupying a position, in the periodic table, either to the left or right of that of the parent element.

Which one of the following alternatives gives the correct position of the daughter element?

A
On emission of $$\alpha$$ particle - 2 groups to the left;
On emission of $$\beta$$ particle- 1 group to the right
B
On emission of $$\alpha$$ particle - 2 groups to the right;
On emission of $$\beta$$ particle- 1 group to the right
C
On emission of $$\alpha$$ particle - 2 groups to the right;
On emission of $$\beta$$ particle- 1 group to the left
D
On emission of $$\alpha$$ particle - 2 groups to the left;
On emission of $$\beta$$ particle- 1 group to the left
Solution
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Correct option is D. On emission of $$\alpha$$ particle - 2 groups to the left;
On emission of $$\beta$$ particle- 1 group to the right
Alpha emission decreases the atomic number by two. So, on the emission of $$\alpha$$-particle daughter element shift 2 group to the left.
Beta emission increases the atomic number by one. So, on the emission of $$\beta$$-particle daughter element shift 1 group to the right.

Hence, option $$D$$ is correct.

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