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Updated on : 2022-09-05

Solution

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Correct option is A)

$∴$ Number of nuclei decayed

$=N_{OA}−2_{6}N_{OA} =6463N_{OA} $

$N_{B}=N_{OB}e_{−λt}=2_{t/t}21 N_{OB} =2_{3}N_{OB} $

$∴$ Number of nuclei decayed

$=N_{OB}−2_{3}N_{OB} =87N_{OB} $

Since $N_{OA}=N_{OB}$

$∴$ ratio of decayed numbers of nuclei

$A&B=64×7N_{OB}63N_{OA}×8 =89 $

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