Horizontal component of the earth's field is 3×10−5T and of dip is 53o. Magnetic field of the earth at that place is

25×10−5T

5×10−5T

85×1010T

9.9×10−8T

A

85×1010T

B

25×10−5T

C

5×10−5T

D

9.9×10−8T

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Solution

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The correct option is B5×10−5T Horizontal component of the earths magnetic fields is given by BH=Bcosδ ⇒B=BHcosδ=3×10−5cos53o =5×10−5T

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