How do you use dimensional analysis to figure out how many seconds are in $4$ years?

Question

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Answer 1

$1 m i n u t e = 60 s e c o n d s$
$1 h o u r = 60 m i n u t e s$
$60 s e c o n d s \times 60 m i n u t e s = 3600 s e c o n d s = 1 h o u r$
$24 h o u r s = 1 d a y$
$365.25 d a y s = 1 y e a r$ (to account for leap years, the likelihood of the extra day out of $4$ years is added.)
$3600 s e c o n d s \times 24 h o u r s = 86, 400 s e c o n d s$
...and finally:
$86, 400 s e c o n d s \times 365.25 d a y s \times 4 = 126, 230, 400 s e c o n d s$ .

Answer 2

1 m i n u t e = 60 s e c o n d s

1 h o u r = 60 m i n u t e s

60 s e c o n d s \times 60 m i n u t e s = 3600 s e c o n d s = 1 h o u r

24 h o u r s = 1 d a y

365.25 d a y s = 1 y e a r

(to account for leap years, the likelihood of the extra day out of

4

years is added.)

3600 s e c o n d s \times 24 h o u r s = 86, 400 s e c o n d s

...and finally:

86, 400 s e c o n d s \times 365.25 d a y s \times 4 = 126, 230, 400 s e c o n d s

.