How long will it be moving it stops the first time-displaystyle t-3frac-pi-omega-displaystyle t-frac-pi-omega-displaystyle t-4frac-pi-omega-displaystyle t-2frac-pi-omega-

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Toppr Admin · Accepted Answer

The equation of force is similar to that in case of a SHM.
Time period of a SHM is given by, $t = (2 \times π) / ω$
But we know that the particle undergoing SHM comes to rest twice in one cycle.
Time when the particle first comes to rest $t = π / ω$

How long will it be moving until it stops for the first time?t=3πωt=πωt=4πωt=2πω

The equation of force is similar to that in case of a SHM.Time period of a SHM is given by, t=(2×π)/ωBut we know that the particle undergoing SHM comes to rest twice in one cycle.Time when the particle first comes to rest t=π/ω

How long will it be moving until it stops for the first time?
$t = 3 \frac{π}{ω}$
$t = \frac{π}{ω}$
$t = 4 \frac{π}{ω}$
$t = 2 \frac{π}{ω}$

The equation of force is similar to that in case of a SHM.
Time period of a SHM is given by, $t = (2 \times π) / ω$
But we know that the particle undergoing SHM comes to rest twice in one cycle.
Time when the particle first comes to rest $t = π / ω$