0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

How many 176 Ω resistors (in parallel) are required to carry 5A on a 220V line?

Solution
Verified by Toppr

Step 1 : Equivalent resistance
Let n be the number of resistors to be connected in parallel
Then, R1=R2=......=Rn=R=176 Ω
Now, 1Req=1R1+1R2+.....1Rn
1Req=nR1=n176
Req=176/n ....(1)

Step 2 : Applying Ohm's law
V=IReq
220=5Req
220=5×176/n (Using Equation (1))
n=4

Hence, four resistors are required.

Was this answer helpful?
244
Similar Questions
Q1
How many 176 Ω resistors (in parallel) are required to carry 5A on a 220V line?
View Solution
Q2
Question 10
How many 176Ω resistors (in parallel) are required to carry 5 A on a 220 V line?
View Solution
Q3

How many 176 W resistors (in parallel) are required to carry 5 A in 220 V line?

View Solution
Q4

How many 176(ohm) resistors in are required to carry 5 A on 220v line

a)in parallel

b)in series

View Solution
Q5
How many 176 Ω?resistor(in parallel) are required to carry 5A in 220V line.
View Solution