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Standard XII
Mathematics
Question
How many days are present from year 2005 to 2008 including these years?
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Solution
Verified by Toppr
1 year
=
365 days.
From 2005 to 2008
=
4 years and 2008 is a leap year i.e., 366 days.
∴
No. of days from year 2005 to 2008
=
(
365
×
4
)
+
1
=
1461
d
a
y
s
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