How many electrons should be removed from a conductor so that it acquires a positive charge of 3-5nC-

Question

Toppr Admin · Accepted Answer

Given-xA0-Charge q-3-5-xD7-10-x2212-9Let the nQ of electron to be removed be nWe know that-xA0-Q-nen-Qen-3-5-xD7-10-x2212-91-6-xD7-10-x2212-19n-2-1875-xD7-10-x2212-9-19n-2-1875-xD7-1010

How many electrons should be removed from a conductor so that it acquires a positive charge of 3.5nC?

Given
Charge $q = 3.5 \times 10^{- 9}$

Let the $n Q$ of electron to be removed be $n$
We know that
$Q = n e$

$n = \frac{Q}{e}$

$n = \frac{3.5 \times 10^{- 9}}{1.6 \times 10^{- 19}}$

$n = 2.1875 \times 10^{- 9 + 19}$

$n = 2.1875 \times 10^{10}$

How many electrons should be removed from a conductor so that it acquires a positive charge of 3.5nC?

Given Charge q=3.5×10−9Let the nQ of electron to be removed be nWe know that Q=nen=Qen=3.5×10−91.6×10−19n=2.1875×10−9+19n=2.1875×1010

Given
Charge $q = 3.5 \times 10^{- 9}$

Let the $n Q$ of electron to be removed be $n$
We know that
$Q = n e$

$n = \frac{Q}{e}$

$n = \frac{3.5 \times 10^{- 9}}{1.6 \times 10^{- 19}}$

$n = 2.1875 \times 10^{- 9 + 19}$

$n = 2.1875 \times 10^{10}$