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chemistry

How many grams of dibasic acid (mol. wt. 200) should be present in 100 mL of the aqueous solution to give 0.1 N ?

A

1 g

B

2 g

C

10 g

D

20 g

Video Explanation

Answer

Correct option is

A

1 g

Equivalent weight of dibasic acid
$= \frac{m o l , w t .}{2} = \frac{2 0 0}{2} = 100$

Strength = 0.1 N, m = ?, V= 100 ml.

From, $m = \frac{E V N}{1 0 0 0} = \frac{1 0 0 \times 1 0 0 \times 0 . 1}{1 0 0 0} = 1 g$

Hence, the correct option is $A$

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