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Question

How many hours does it take to reduce 3 moles of Fe3+ to Fe2+ with 2.0A current intensity?

Solution
Verified by Toppr

Given, Current =2.0 Ampere
3Fe3++3e3Fe2+
Charge required =Faraday=3×96500 coulomb
=289500 coulomb
We know, Charge=Current×Time
or Time =2895002
=144750 sec
=40.20 hrs.

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