How many liters of hard water may contain 60 mg of MgSO-4 in order to have a degree of hardness of 25 ppm-

Question

Toppr Admin · Accepted Answer

Hardness -in ppm- - WeightofMgSO4-inmg-Volumeofwater-inL-x2234- 25-60Volume-x2234- Volume-2-4 litres-x2234- 2-4 litres of hard water contains 60 mg of MgSo4 to have degree of hardness 25 ppm-

How many liters of hard water may contain 60 mg of $M g S O_{4}$ in order to have a degree of hardness of 25 ppm?

Hardness (in ppm) = $\frac{W e i g h t o f M g S O_{4} (i n m g)}{V o l u m e o f w a t e r (i n L)}$
$∴$ $25 = \frac{60}{V o l u m e}$
$∴$ $V o l u m e = 2.4$ litres.

$∴$ $2.4$ litres of hard water contains $60$ mg of $M g S o_{4}$ to have degree of hardness $25$ ppm.

How many liters of hard water may contain 60 mg of MgSO4 in order to have a degree of hardness of 25 ppm?

Hardness (in ppm) = WeightofMgSO4(inmg)Volumeofwater(inL)∴ 25=60Volume∴ Volume=2.4 litres.∴ 2.4 litres of hard water contains 60 mg of MgSo4 to have degree of hardness 25 ppm.

How many liters of hard water may contain 60 mg of $M g S O_{4}$ in order to have a degree of hardness of 25 ppm?

Hardness (in ppm) = $\frac{W e i g h t o f M g S O_{4} (i n m g)}{V o l u m e o f w a t e r (i n L)}$
$∴$ $25 = \frac{60}{V o l u m e}$
$∴$ $V o l u m e = 2.4$ litres.

$∴$ $2.4$ litres of hard water contains $60$ mg of $M g S o_{4}$ to have degree of hardness $25$ ppm.