How many ml of water must be added to 48 ml of alcohol to a solution that contains 25- alcohol-4864192144

Question

Toppr Admin · Accepted Answer

Let us suppose that we add x ml of water to make the required solution-xA0-Then- 25- of -48-x-48-x21D2-25100 of -48-x-48-x21D2-25-xD7-48-x-100-48-x21D2-48-x-48-xD7-4-x21D2-x-192-x2212-43-144ml-

How many ml of water must be added to $48 m l$ of alcohol to make a solution that contains $25 %$ alcohol?
$48$
$64$
$192$
$144$

Let us suppose that we add $x$ ml of water to make the required solution.
Then, $25 %$ of $(48 + x) = 48$
$\Rightarrow \frac{25}{100}$ of $(48 + x) = 48$
$\Rightarrow \frac{25 \times (48 + x)}{100} = 48$
$\Rightarrow 48 + x = 48 \times 4$
$\Rightarrow x = 192 - 43 = 144 m l .$

How many ml of water must be added to 48ml of alcohol to make a solution that contains 25% alcohol?4864192144

Let us suppose that we add x ml of water to make the required solution. Then, 25% of (48+x)=48⇒25100 of (48+x)=48⇒25×(48+x)100=48⇒48+x=48×4⇒x=192−43=144ml.

How many ml of water must be added to $48 m l$ of alcohol to make a solution that contains $25 %$ alcohol?
$48$
$64$
$192$
$144$

Let us suppose that we add $x$ ml of water to make the required solution.
Then, $25 %$ of $(48 + x) = 48$
$\Rightarrow \frac{25}{100}$ of $(48 + x) = 48$
$\Rightarrow \frac{25 \times (48 + x)}{100} = 48$
$\Rightarrow 48 + x = 48 \times 4$
$\Rightarrow x = 192 - 43 = 144 m l .$