How many natural numbers are there between $$102$$ and $$112$$ ? What fraction of them are prime numbers?
The nature numbers from $$102$$ to $$112$$ are : $$103, 104,105, 106, 107, 108, 109, 110, 111$$
Total number of natural number $$= 9$$
Out of these prime numbers are : $$ 103 , 107, 109 $$
$$\therefore$$ Total number of these prime numbers $$= 3$$
Required fraction $$= \dfrac{3}{9}$$ $$= \dfrac{1}{3}$$