How many spherical bullets can be made out of a lead cylinder $15$ cm high and with base radius $3$ cm, each bullet being $5$ mm in diameter?

Question

How many spherical bullets can be made out of a lead cylinder 15cm high and with base radius 3cm- each bullet being 5mm in diameter-6000726064807800

Toppr Admin · Accepted Answer

Volume of cylinder V-x3C0-r2h-9-xD7-15-x3C0-135-x3C0-Volume of bullet v-43-x3C0-r3-43-xD7-2-53-xD7-10-x2212-3-x3C0-Number of bullets -Vv-135-x3C0-xD7-103-xD7-34-xD7-2-53-xD7-x3C0-6480

How many spherical bullets can be made out of a lead cylinder $15$ cm high and with base radius $3$ cm, each bullet being $5$ mm in diameter?
$6000$
$7260$
$6480$
$7800$

Volume of cylinder $V = π r^{2} h = 9 \times 15 π = 135 π$
Volume of bullet $v = \frac{4}{3} π r^{3} = \frac{4}{3} \times {2.5}^{3} \times 10^{- 3} π$

Number of bullets $= \frac{V}{v} = \frac{135 π \times 10^{3} \times 3}{4 \times {2.5}^{3} \times π} = 6480$

How many spherical bullets can be made out of a lead cylinder 15cm high and with base radius 3cm, each bullet being 5mm in diameter?6000726064807800

Volume of cylinder V=πr2h=9×15π=135πVolume of bullet v=43πr3=43×2.53×10−3πNumber of bullets =Vv=135π×103×34×2.53×π=6480

How many spherical bullets can be made out of a lead cylinder $15$ cm high and with base radius $3$ cm, each bullet being $5$ mm in diameter?
$6000$
$7260$
$6480$
$7800$

Volume of cylinder $V = π r^{2} h = 9 \times 15 π = 135 π$
Volume of bullet $v = \frac{4}{3} π r^{3} = \frac{4}{3} \times {2.5}^{3} \times 10^{- 3} π$

Number of bullets $= \frac{V}{v} = \frac{135 π \times 10^{3} \times 3}{4 \times {2.5}^{3} \times π} = 6480$