How much electricity is required in coulomb for the oxidation of:
(i) $1 m o l$ of $H_{2} O$ to $O_{2}$ ?
(ii) $1 m o l$ of $F e O$ to $F e_{2} O_{3}$ ?

Question

How much electricity is required in coulomb the oxidation of-i- 1 mol of H-2-O to O-2-ii- 1 mol of FeO to Fe-2-O-3-

Toppr Admin · Accepted Answer

-i- H2O-x2192-2H-12O2-2e-x2212-Oxidation of one mole of water will require 2-xD7-96500-1-93-xD7-105C-ii- Fe2-x2192-Fe3-Oxidation of one mole of Fe2- will require 1-xD7-96500-96500C-

How much electricity is required in coulomb for the oxidation of:(i) 1 mol of H2O to O2?(ii) 1 mol of FeO to Fe2O3?

(i) H2O→2H++12O2+2e−Oxidation of one mole of water will require 2×96500=1.93×105C.(ii) Fe2+→Fe3+Oxidation of one mole of Fe2+ will require 1×96500=96500C.

How much electricity is required in coulomb for the oxidation of:
(i) $1 m o l$ of $H_{2} O$ to $O_{2}$ ?
(ii) $1 m o l$ of $F e O$ to $F e_{2} O_{3}$ ?

(i) $H_{2} O \to 2 H^{+} + \frac{1}{2} O_{2} + 2 e^{-}$
Oxidation of one mole of water will require $2 \times 96500 = 1.93 \times 10^{5} C$ .

(ii) $F e^{2 +} \to F e^{3 +}$
Oxidation of one mole of $F e^{2 +}$ will require $1 \times 96500 = 96500 C$ .