How much length of the iron sheet 11 cm wide is required making an cylinder 15 cm high and 7 cm as base radius displaystyle left - pi -22-7 right -

Question

Toppr Admin · Accepted Answer

Surface of an open cylinder - area of the iron sheet-x3C0-r2-2-x3C0-rh-227-xD7-72-2-xD7-227-xD7-7-xD7-15-154-660-cm2-814cm2-x2234- Length of the sheet-xA0-814-xF7-11-cm-74cm

How much length of the iron sheet $11$ cm wide is required for making an open cylinder $15$ cm high and $7$ cm as base radius $(π = 22 / 7)$ ?

Surface of an open cylinder = area of the iron sheet
$= π r^{2} + 2 π r h$
$= \frac{22}{7} \times 7^{2} + 2 \times \frac{22}{7} \times 7 \times 15$
$= (154 + 660) c m^{2}$
$= 814 c m^{2}$
$∴$ Length of the sheet
$= (814 \div 11) c m$
$= 74 c m$

How much length of the iron sheet 11 cm wide is required for making an open cylinder 15 cm high and 7 cm as base radius (π=22/7)?

Surface of an open cylinder = area of the iron sheet=πr2+2πrh=227×72+2×227×7×15=(154+660)cm2=814cm2∴ Length of the sheet =(814÷11)cm=74cm

How much length of the iron sheet $11$ cm wide is required for making an open cylinder $15$ cm high and $7$ cm as base radius $(π = 22 / 7)$ ?

Surface of an open cylinder = area of the iron sheet
$= π r^{2} + 2 π r h$
$= \frac{22}{7} \times 7^{2} + 2 \times \frac{22}{7} \times 7 \times 15$
$= (154 + 660) c m^{2}$
$= 814 c m^{2}$
$∴$ Length of the sheet
$= (814 \div 11) c m$
$= 74 c m$