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Question
How much pure alcohol should be added to
4
0
0
m
l
of strength
1
5
%
to make its strength
3
2
%
?
A
5
0
m
l
B
7
5
m
l
C
1
0
0
m
l
D
1
5
0
m
l
Medium
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Solution
Verified by Toppr
Correct option is C)
The amount of alcohol in
4
0
0
m
l
solution of
1
5
%
strength
=
4
0
0
×
1
0
0
1
5
m
l
=
6
0
m
l
Let the required amount of alcohol to be added
=
x
ml.
It will increase the amount of the solution by
x
ml.
∴
The amount of alcohol now
=
(
6
0
+
x
)
m
l
and the amount of the solution
=
(
4
0
0
+
x
)
m
l
.
Then, the strength
=
3
2
%
=
4
0
0
+
x
6
0
+
x
=
1
0
0
3
2
⇒
2
5
x
+
1
5
0
0
=
3
2
0
0
+
8
x
⇒
1
7
x
=
1
7
0
0
⇒
x
=
1
0
0
.
So, the required amount of pure alcohol to be added
=
1
0
0
m
l
.
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