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Correct option is C)

$=400×10015 ml=60ml$

Let the required amount of alcohol to be added $=x$ ml.

It will increase the amount of the solution by $x$ ml.

$∴$ The amount of alcohol now $=(60+x)ml$

and the amount of the solution$=(400+x)ml$.

Then, the strength $=32%=400+x60+x =10032 $

$⇒25x+1500=3200+8x⇒17x=1700⇒x=100$.

So, the required amount of pure alcohol to be added $=100ml$.

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