How much volume of air will be needed complete combustion of 10 lit- of ethane-135 lit-175 lit-35 lit-205 lit-

Question

Toppr Admin · Accepted Answer

Balance equation-2C2H6-7O2-x2192-4CO2-6H2OAccording to reaction 7 mole of oxygen required for 2 mole of ethane so for 10 lit of ethane 35 lit of oxygen is required- As air contains only 20- oxygen so volume of air required is 35-xD7-5-175 lit-

How much volume of air will be needed for complete combustion of 10 lit. of ethane?
135 lit.
175 lit.
35 lit.
205 lit.

Balance equation:
$2 C_{2} H_{6} + 7 O_{2} \to 4 C O_{2} + 6 H_{2} O$
According to reaction 7 mole of oxygen required for 2 mole of ethane so for 10 lit of ethane 35 lit of oxygen is required. As air contains only 20% oxygen so volume of air required is $35 \times 5 = 175$ lit.

How much volume of air will be needed for complete combustion of 10 lit. of ethane?135 lit.175 lit.35 lit.205 lit.

Balance equation:2C2H6+7O2→4CO2+6H2OAccording to reaction 7 mole of oxygen required for 2 mole of ethane so for 10 lit of ethane 35 lit of oxygen is required. As air contains only 20% oxygen so volume of air required is 35×5=175 lit.

How much volume of air will be needed for complete combustion of 10 lit. of ethane?
135 lit.
175 lit.
35 lit.
205 lit.

Balance equation:
$2 C_{2} H_{6} + 7 O_{2} \to 4 C O_{2} + 6 H_{2} O$
According to reaction 7 mole of oxygen required for 2 mole of ethane so for 10 lit of ethane 35 lit of oxygen is required. As air contains only 20% oxygen so volume of air required is $35 \times 5 = 175$ lit.