How quickly can you do this- Fill appropriate sign- -dfrac -3-4-square dfrac -7-8-

Question

Toppr Admin · Accepted Answer

-dfrac -3-4- - -dfrac -3-times 2-4-times 2- - -dfrac -6-8-As the denominators of -dfrac -6-8- and -dfrac -7-8- are same- the fraction having the greater numerator will be greater-Hence- -dfrac -3-4- -lt- -dfrac -7-8-

How quickly can you do this? Fill appropriate sign. $$('<', '=', '>')$$
$$\dfrac {3}{4}\square \dfrac {7}{8}$$

$$\dfrac {3}{4} = \dfrac {3\times 2}{4\times 2} = \dfrac {6}{8}$$
As the denominators of $$\dfrac {6}{8}$$ and $$\dfrac {7}{8}$$ are same, the fraction having the greater numerator will be greater.
Hence, $$\dfrac {3}{4} < \dfrac {7}{8}$$.

How quickly can you do this? Fill appropriate sign. $$('<', '=', '>')$$$$\dfrac {3}{4}\square \dfrac {7}{8}$$

$$\dfrac {3}{4} = \dfrac {3\times 2}{4\times 2} = \dfrac {6}{8}$$As the denominators of $$\dfrac {6}{8}$$ and $$\dfrac {7}{8}$$ are same, the fraction having the greater numerator will be greater.Hence, $$\dfrac {3}{4} < \dfrac {7}{8}$$.

How quickly can you do this? Fill appropriate sign. $$('<', '=', '>')$$
$$\dfrac {3}{4}\square \dfrac {7}{8}$$

$$\dfrac {3}{4} = \dfrac {3\times 2}{4\times 2} = \dfrac {6}{8}$$
As the denominators of $$\dfrac {6}{8}$$ and $$\dfrac {7}{8}$$ are same, the fraction having the greater numerator will be greater.
Hence, $$\dfrac {3}{4} < \dfrac {7}{8}$$.