Hydroboration-oxidation of CH-3-CH- CH-2- produces-CH-3-CH-2-CH-2-OHCH-3-CH-OH-CH-3-CH-3-CH-OH-CH-2-OHCH-3-COCH-3-

Question

Toppr Admin · Accepted Answer

A Hydroboration-oxidation reaction is a two-step organic reaction that converts an alkene into neutral alcohol by the net addition of water across the double bond- it follows Anti-Markownikoff-apos-s rule-

Hydroboration-oxidation of $C H_{3} C H = C H_{2}$ produces:
$C H_{3} C H_{2} C H_{2} O H$
$C H_{3} C H (O H) C H_{3}$
$C H_{3} C H (O H) C H_{2} O H$
$C H_{3} C O C H_{3}$

A Hydroboration-oxidation reaction is a two-step organic reaction that converts an alkene into neutral alcohol by the net addition of water across the double bond. it follows Anti-Markownikoff's rule.

Hydroboration-oxidation of CH3CH=CH2 produces:CH3CH2CH2OHCH3CH(OH)CH3CH3CH(OH)CH2OHCH3COCH3

A Hydroboration-oxidation reaction is a two-step organic reaction that converts an alkene into neutral alcohol by the net addition of water across the double bond. it follows Anti-Markownikoff's rule.

Hydroboration-oxidation of $C H_{3} C H = C H_{2}$ produces:
$C H_{3} C H_{2} C H_{2} O H$
$C H_{3} C H (O H) C H_{3}$
$C H_{3} C H (O H) C H_{2} O H$
$C H_{3} C O C H_{3}$