Hydrolysis of one mole of peroxodisulphuric acid produces one mole of sulphuric acid and one mole of peroxomonosulphuric acid.

$H_{2} S_{2} O_{8} + H_{2} O ⟶ H_{2} S O_{4} + H_{2} S O_{5}$

Option (C) is correct.

Question

Hydrolysis of one mole of peroxodisulphuric acid produces one mole of sulphuric acid and one mole of peroxomonosulphuric acid.

$H_{2} S_{2} O_{8} + H_{2} O ⟶ H_{2} S O_{4} + H_{2} S O_{5}$

Option (C) is correct.

Toppr Admin · Accepted Answer

Hydrolysis of one mole of peroxodisulphuric acid produces one mole of sulphuric acid and one mole of peroxomonosulphuric acid-H2S2O8-H2O-x27F6-H2SO4-H2SO5Option -C- is correct-

Hydrolysis of one mole of peroxodisulphuric produces :two moles of sulphuric acid.two moles of peroxomonosulphuric acid.one mole of sulphuric acid and one mole of peroxomonosulphuric acid.one mole each of sulphuric acid, peroxomonosulphuric acid and hydrogen peroxide.

Hydrolysis of one mole of peroxodisulphuric acid produces one mole of sulphuric acid and one mole of peroxomonosulphuric acid.H2S2O8+H2O⟶H2SO4+H2SO5Option (C) is correct.

Hydrolysis of one mole of peroxodisulphuric produces :
two moles of sulphuric acid.
two moles of peroxomonosulphuric acid.
one mole of sulphuric acid and one mole of peroxomonosulphuric acid.
one mole each of sulphuric acid, peroxomonosulphuric acid and hydrogen peroxide.

Hydrolysis of one mole of peroxodisulphuric acid produces one mole of sulphuric acid and one mole of peroxomonosulphuric acid.

$H_{2} S_{2} O_{8} + H_{2} O ⟶ H_{2} S O_{4} + H_{2} S O_{5}$

Option (C) is correct.