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(i) \( \Delta \mathrm { AOD } \cong \Delta \mathrm { BOC } \) and \( ( \mathrm { ii } ) \mathrm { AD } \| \mathrm { BC } \) Solation: is You may observe that in \( \Delta \) AOD and \( \Delta \) BOC

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Q1
In the given figure, ABCD is a trapezium, Diagonals AC and BD interset at Q Prove that the area of ΔAOD is the same as ΔBOC
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Q2

In the given, ABCD is a quadrilateral with diagonals AC and BD intersecting at point O. Hence, area of Δ AOD × area of Δ BOC = area of Δ AOB × area of Δ COD.


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Q3
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