0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

I) $$PhO^{\ominus }$$
II) $$CH_3S^{\ominus }$$
III) $$OH^{\ominus }$$
IV) $$Me^{\ominus }$$
Which of this is more acidic and least basic.

Solution
Verified by Toppr

Was this answer helpful?
0
Similar Questions
Q1
The decreasing basic character of the following is:
I. PhO II. CH3S III. OH IV. MeO
View Solution
Q2
The decreasing basic character of the following is:
I. PhO
II. CH3S
III. OH
IV. MeO
View Solution
Q3
The decreasing basic character of the following is:
(I) PhO (II) CH3S (III) OH (IV) MeO

View Solution
Q4
The decreasing basic order of the following is:
i.CN ii.OH iii.OMe iv.CH3 v.H
View Solution
Q5
The basicity of compounds I, II, III and IV varies in the order:
$$\underset { I }{ { CH }_{ 3 }{ NH }_{ 2 } } $$, $$\underset { II }{ { (CH }_{ 3 }{ )_{ 2 }NH } } $$, $$\underset { III }{ { (CH }_{ 3 }{ )_{ 3 }N } } $$, $$\underset { IV }{ { C }_{ 6 }{ H }_{ 5 }{ CH }_{ 2 }{ NH }_{ 2 } } $$
View Solution