I- The range of the f-x-cos-x- -dfrac-pi-2-x-dfrac-pi-2 is -1- cos1- cos 2-II- Every periodic is one-one function-only I is trueonly II is trueboth I and II are trueneither I nor II are true

Question

Toppr Admin · Accepted Answer

From graph you can find the range -amp- also justify that every periodic function is not one-one function-

$I$ : The range of the function $f (x) = cos [x]$ for $- \frac{π}{2} < x < \frac{π}{2}$ is ${1, cos 1, cos 2}$ .
$I I$ : Every periodic function is one-one function.
only I is true
only II is true
both I and II are true
neither I nor II are true

From graph you can find the range & also justify that every periodic function is not one-one function.

I: The range of the function f(x)=cos[x] for −π2<x<π2 is {1,cos1,cos2}.II: Every periodic function is one-one function.only I is trueonly II is trueboth I and II are trueneither I nor II are true

From graph you can find the range & also justify that every periodic function is not one-one function.

$I$ : The range of the function $f (x) = cos [x]$ for $- \frac{π}{2} < x < \frac{π}{2}$ is ${1, cos 1, cos 2}$ .
$I I$ : Every periodic function is one-one function.
only I is true
only II is true
both I and II are true
neither I nor II are true