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Question

(i) What number should be added to $$\dfrac{5}{12} $$ to get $$2 \dfrac{2}{8}$$ ?
(ii) What number should be subtracted from $$5$$ to get $$1 \dfrac{5}{13}$$ ?

Solution
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(i) Let the number to be added $$= x$$
$$\therefore \dfrac{5}{12} + x = 2 \dfrac{3}{8}$$
$$\therefore \, Required \,number\, \left(x\right) = 2 \dfrac{3}{8} - \dfrac{5}{12} $$
$$x = \dfrac{19}{8} - \dfrac{5}{12}$$
$$= \dfrac{57 - 10 }{24} = \dfrac{47}{24} = 1\dfrac{23}{24}$$
(ii) Let the number to be subtracted $$= x$$
$$\therefore 5 - x = 1\dfrac{1}{13}$$
Required number $$\left(x\right) = 5 - 1\dfrac{5}{13}$$
$$x = \dfrac{5}{1} - \dfrac{18}{13} $$
$$ = \dfrac{65 - 18}{13} = \dfrac{47}{13} = 3 \dfrac{8}{13}$$

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