Identify correct order of average molecular dipole moment.
All are incorrect.
$P {C l}_{3} F_{2} > N_{2} O_{4 (g)} > N_{2} O_{4 (s)}$
$P {C l}_{3} F_{2} < N_{2} O_{4 (g)} = N_{2} O_{4 (s)}$
$P {C l}_{3} F_{2} < N_{2} O_{4 (g)} < N_{2} O_{4 (s)}$

Question

Identify correct order of average molecular dipole moment-All are incorrect-P-Cl-3-F-2- -N-2-O-4-g- -N-2-O-4-s-P-Cl-3-F-2- -N-2-O-4-g- -N-2-O-4-s-P-Cl-3-F-2- -N-2-O-4-g- -N-2-O-4-s-

Toppr Admin · Accepted Answer

Correct Option -x2212-DReason- PCl3F2 has a symmetrical -amp- thus has a zero dipole moment- Increasing dipole moments N from N2O4-s- to N2O4-g-is due to the fact that dipole moment-charge-distance-

Identify correct order of average molecular dipole moment.All are incorrect.PCl3F2>N2O4(g)>N2O4(s)PCl3F2<N2O4(g)=N2O4(s)PCl3F2<N2O4(g)<N2O4(s)

Correct Option −DReason:- PCl3F2 has a symmetrical & thus has a zero dipole moment. Increasing dipole moments N from N2O4(s) to N2O4(g)is due to the fact that dipole moment=charge*distance.

Identify correct order of average molecular dipole moment.
All are incorrect.
$P {C l}_{3} F_{2} > N_{2} O_{4 (g)} > N_{2} O_{4 (s)}$
$P {C l}_{3} F_{2} < N_{2} O_{4 (g)} = N_{2} O_{4 (s)}$
$P {C l}_{3} F_{2} < N_{2} O_{4 (g)} < N_{2} O_{4 (s)}$

Correct Option $- D$
Reason:- $P C l_{3} F_{2}$ has a symmetrical & thus has a zero dipole moment. Increasing dipole moments N from $N_{2} O_{4}$ $_{(s)}$ to $N_{2} O_{4}$ $_{(g)}$ is due to the fact that dipole moment=charge*distance.