Identify Y in the following reaction-C-2-H-5-NH-2- xrightarrow -NaNO-2-HCl- -X- xrightarrow -H-2-O- Y- C - 2 - H - 5 - N - 2 -Cl- C - 2 - H - 5 -Cl- C - 2 - H - 5 -OH- C - 2 - H - 6 -

Question

Toppr Admin · Accepted Answer

Ethyl amine reacts with sodium nitrite and HCl in cold condition to form unstable diazonium salt (compound X) which decomposes to form ethanol (compound Y).

In this process, nitrogen gas is liberated.
The reaction is as follows:

$C_{2} H_{5} {N H}_{2} e t h y l a m i n e H C l - --- \to {N a N O}_{2} [C_{2} H_{5} N_{2}^{+} C l^{-}] [X] H_{2} O - - \to C_{2} H_{5} O H [Y]$

Hence, $Y$ is $C_{2} H_{5} O H$ .

Identify Y in the following reaction.C2H5NH2HCl−−−−→NaNO2[X]H2O−−→YC2H5N2ClC2H5ClC2H5OHC2H6

Identify $Y$ in the following reaction.
$C_{2} H_{5} {N H}_{2} H C l - --- \to {N a N O}_{2} [X] H_{2} O - - \to Y$
$C_{2} H_{5} N_{2} C l$
$C_{2} H_{5} C l$
$C_{2} H_{5} O H$
$C_{2} H_{6}$