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Question

If 1st ionisation energy of Helium (He) atom is 25.6 eV/atom then sum of IE1 and IE2 per atom of Helium (He) would be:
  1. 85.7 eV
  2. 51.2 eV
  3. 60 eV
  4. 80.04 eV

A
60 eV
B
85.7 eV
C
51.2 eV
D
80.04 eV
Solution
Verified by Toppr

The first IE of He is much higher than that of its' second IE as the first e removed is fully filled shell, i.e; 1s2.
So, IE1 of He=25.6eV
Then He+ is isoelectronic to hydrogen atom with 1s1 configuration.
HE2=|E1(He+)|
=22×13.6eV12
=54.44eV
IE1+IE2=25.6+54.4=80.04eV

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