If 8g mol of PCl5 heated in a closed vessel of 10L capacity and 25% of its dissociates into PCl3 and Cl2 at the equilibrium then value of Kp will be equal to
P/30
2/3P
3/2P
P/15
A
P/30
B
3/2P
C
P/15
D
2/3P
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Solution
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PCl5(g)⇌PCl3+Cl210L vessel
25% dissociated moles of PCl5=8208=126
α=0.25
PCl5⇌PCl3+Cl2
At t=012600
At 126(1−α)α26α/26
t=eq
Let P be total pressure at equilibrium.
PCl2=α26126(1+α)P⇒P/5
PPCl3=P/5
PPCl5=3P/5KP=P/5.P/53P/5⇒P15
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