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Question

If a = -9 and b = -6, show that (a-b) $$\neq$$ (b-a)

Solution
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From the Commutative law of Subtraction
Left hand side (LHS),
$$= {(-9)-(-6)}$$
$$= {-9+6}$$
$$=-{9-6}$$
(Take out the –ve sign outside and do subtract smaller from bigger number)
$$=-{3}$$
$$=-3$$
Right hand side (RHS),
$$= {(-6)-(-9)}$$
$$= {-6+9}$$
$$=-{6-9}$$
(Take out the –ve sign outside and do subtract smaller from bigger number)
$$=-{-3}$$
$$=3$$
By comparing LHS and RHS
$$LHS \neq RHS$$

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