If $A=B=1$, then in terms of Boolean algebra the value of $A.B+A$ is not equal to

For $A=B=1$,

$\Rightarrow A.B+B=1.1+1=1+1=1$

Therefore, 

(A) $B.A+B=1.1+1=1+1=1$

(B) $B+A=1+1=1$

(C) $B=1$

(D) $\bar{A}.B=1.1+1=\bar{1}.1=0.1=0$

Hence, option D is the correct answer.