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Question

# If a bar magnet in magnetic moment m is deflected from an angle θ in a uniform magnetic field of induction B, the work done in reversing the direction is MBsinθMBMB(1−cosθ)MBcosθ

A
MB
B
MBcosθ
C
MBsinθ
D
MB(1cosθ)
Solution
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#### Now lets assume that the bar magnetic is initially placed parallel to the field the initial potential energy will be Ui=−−→M.→B=−MBcos0=−MBNow when it is deflected by an angle θ then Uf=−−→M.→B=−MBcosθNow we know that the work done = −ΔUΔU=Ui−UfΔU=−MB(1−cosθ)therefore, work done =MB(1−cosθ).

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