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Question

If a bar magnet in magnetic moment m is deflected from an angle θ in a uniform magnetic field of induction B, the work done in reversing the direction is
  1. MBsinθ
  2. MB
  3. MB(1cosθ)
  4. MBcosθ

A
MB
B
MBcosθ
C
MBsinθ
D
MB(1cosθ)
Solution
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Now lets assume that the bar magnetic is initially placed parallel to the field the initial potential energy will be Ui=M.B=MBcos0=MB
Now when it is deflected by an angle θ then Uf=M.B=MBcosθ
Now we know that the work done = ΔU
ΔU=UiUf
ΔU=MB(1cosθ)
therefore, work done =MB(1cosθ).

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