If a charged body experiences a force of repulsion of magnitude F from a charge of q0β, the electric field E of the charged body at a point lying not in between the 2 charges but on the same line joining two charges, is :
A
q0βFβ
B
<q0βFβ
C
>q0βFβ
D
F
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Updated on : 2022-09-05
Solution
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Correct option is C)
Electric field of a charged body due to charge: q0β=E0β=q0βFβ But the electric field of the charged body at a not in between two charges means the sum of field due to all point charges,i.e., E=q0βFβ+βiβqiβFβ So, E>q0βFβ
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